<PRE><B>Question 586366</B>
What is the probability of having two aces, two kings, and a queen in a five-card poker hand?
---
# of ways to succeed: 4C2*4C2*4C1 = 6*6*4 = 144 
----
# of random hands of 5: 52C5 = 2598960
----
P(2A and 2K and 1Q) = 144/2598960 = 0.0000554407

===========================
Cheers,
Stan H.</PRE>