<PRE><B>Question 586355</B>
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Please note the instructions for posting; in particular the one that says one question per post.


2.  &lt;i&gt;&lt;u&gt;the perpendicular bisector of the segment.&lt;/u&gt;&lt;/i&gt;


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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