Question 586328
{{{3e^(x+1) -2=0}}}
{{{3e^(x+1) =2}}} divide by 3
{{{e^(x+1) =2/3}}} take the log of both sides with the base e
 {{{ln(e^(x+1)) =ln(2/3)}}} Use the property {{{ln(a^b)=b*lna}}}, then {{{ln(e^(x+1))=(x+1)*lne=(x+1)*1=x+1}}} 
{{{x+1 =ln(2/3)}}}
{{{x=ln(2/3)-1}}}