Question 585909

{{{(x^2+8)(x^3+7x-3)}}} Start with the given expression.



{{{x^2(x^3+7x-3)+8(x^3+7x-3)}}} Expand.



{{{(x^2)*(x^3)+(x^2)*(7x)+(x^2)*(-3)+(8)*(x^3)+(8)*(7x)+(8)*(-3)}}} Distribute.



{{{x^5+7*x^3-3*x^2+8*x^3+56*x-24}}} Multiply.



{{{x^5+15*x^3-3*x^2+56*x-24}}} Now combine like terms.



 So {{{(x^2+8)(x^3+7x-3)}}} expands to {{{x^5+15x^3-3x^2+56x-24}}}.



In other words, {{{(x^2+8)(x^3+7x-3)=x^5+15x^3-3x^2+56x-24}}} for all values of x.


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