Question 585749
<pre>
           17<sup>-x-3</sup> = 15<sup>-8x</sup>

      log(17<sup>-x-3</sup>) = log(16<sup>-8x</sup>)

  (-x-3)·log(17) = (-8x)·log(16)

Let log(17) = A
Let log(16) = B

        (-x-3)·A = (-8x)·B

         A(-x-3) = -8Bx

        -Ax - 3A = -8Bx

       -Ax + 8Bx = 3A

      x(-A + 8B) = 3A

              x = {{{3A/(-A+8B)}}}

Replace A by log(17) = 1.230448921

Replace B by log(16) = 1.204119983

              x = {{{(3(1.230448921))/(-1.230448921+8(1.204119983))}}} 

              x = .4393147228

Edwin</pre>