Question 585624
"triple a number divided by 5 is at least 38" translates to {{{3n/5 >= 38}}}, now let's solve for n


{{{3n/5 >= 38}}}


{{{3n >= 38*5}}}


{{{3n >= 190}}}


{{{n >= 190/3}}}



So the solution is {{{n >= 190/3}}} which in decimal form is approximately {{{n >= 63.333}}}


So the number is at least 63.333

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