Question 585614
f(x)= x^3-5x^2+5x+3 
Find the zeros of and their multiplicity 
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I graphed it and found zeroes at x = -0.4142,
and x = 3 (multiplicity 2).
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{{{graph(400,400,-10,10,-10,10,x^3-5x^+5x+3)}}}
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Cheers,
Stan H.
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