Question 585590
Call the consecutive even integers
{{{ n }}}, and {{{ n + 2 }}}
given:
{{{ n*( n + 2 ) = 528 }}}
{{{ n^2 + 2n = 528 }}}
Complete the square
{{{ n^2 + 2n + (2/2)^2 = 528 + (2/2)^2 }}}
{{{  n^2 + 2n + 1 = 528 + 1 }}}
{{{ ( n + 1 )^2 = 529 }}}
{{{ ( n + 1 )^2 = 23^2 }}}
{{{ n +1 = 23 }}}
{{{ n = 22 }}}
{{{ n + 2 = 24 }}}
The numbers are 22, and 24
check 
{{{ 22*24 = 528 }}}
OK