Question 585525
Is 18x sqr + 4x -1 =0 a real solution, two real solution, or have two imaginary solutions?
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{{{18x^2 + 4x - 1 = 0}}}
Find the discriminant
{{{Disc = b^2 - 4ac = 4^2 - 4*18*-1 = 16 + 72 = 88}}}
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If the Disc > 0, there are 2 real solutions.
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*[invoke solve_quadratic_equation 18,4,-1]