<PRE><B>Question 55097</B>
Can someone help me on this problem.  I have gotten two different results and not sure which was is right.

  The length of a rectangle is 2 cm more than twice its width.  f the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle

ans:
   let length of the rectangle = l
       width of the rectangle = w

hence according to the question ,
  
    l = 2+2*w  ----I
and perimeter of rectangle = 2(l+w) 
                           = 2((2+2w)+w)        (putting l from I)
                           =2(2+3w)=52
                         or 2+3w = 21
                         or 3w=19
                         or w = 19/3
                     hence l = 2+2*19/3 = 44/3    
 
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