Question 55097
Let w represent the width, then (2w+2) is the length ("2 more than twice its width").  Because a rectangle's perimeter is 2(l+w), your rectangle's perimeter becomes {{{2((2w+2)+w)=52}}}.  Expanding the equation gives us {{{2(3w+2)=52}}} which further expands to {{{6w+4=52}}}.  Solving for w gives us {{{w=8}}}, which means the length is {{{2*8+2}}} which is 18.  To prove that the rectangle is 8 by 18, it's perimeter should be 52:  8+8+18+18=52.  Yeah!