Question 585345
Solve for x:
{{{27^(4x) = 9}}} Replace: {{{27 = 3^3}}} and {{{9 = 3^2}}}
{{{(3^3)^(4x) = 3^2}}} Simplify.
{{{3^(12x) = 3^2}}} The bases are equal so the exponents must be equal.
{{{12x = 2}}} Divide by 12.
{{{x = 2/12}}} Simplify.
{{{x = 1/6}}}