Question 585300
Let the present age of father be x and the son be y.

Now,   x = 4y   ---------- (1)

After 16 years,
 
    age of father will be x+ 16
    age of son will be y +16

Therefore,    x + 16 = 2( y + 16)
              x + 16 = 2y + 32
              x = 2y + 16
 or          4y = 2y + 16     {Using equation (a)}
             2y = 16
              y = 8

Plugging back the value of y in equation (1), we get:
 x = 4*8 = 32

Hence, the present age of father is 32 years and present age of son is 8 years.