Question 585207
If x^2 = 6x-9  , then what value is 5x^2+x-8 ? The hint is to solve for x first.
5(6x-9)+x-8=5x^2+x-8

5(6x-9)=5x^2

6x-9=x^2

x^2-6x+9=0
(x-3)(x-3)=0
so x=3

5x^2+x-8=5*9+3-8=45-5=40 The answer is 40