Question 585197
{{{50x-75<50/x}}} multiply both sides by x so we wouldn't have to deal with fractions
{{{50x^2-75x<50}}}
{{{50x^2-75x-50<0}}} factor 25
{{{25(2x^2-3x-2)<0}}} use quadratic formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (3 +- sqrt( 9+16 ))/(4) }}} 
{{{x = (3 +- sqrt( 25 ))/(4) }}} 
{{{x = (3 +- 5)/(4) }}} 
{{{x = (3 + 5)/(4) }}} 
{{{x = (8)/(4)=2 }}} OR
{{{x = (3 - 5)/(4) }}} 
{{{x = (-2)/(4)=-1/2 }}}