Question 55096
factor completly   {{{3a^4b+3ab^4}}}
First factor out the GCF (greatest common factor):
{{{3ab*a^3+3ab*b^3}}}
{{{3ab(a^3+b^3)}}}
The sum of cubes is factored by the formula: {{{highlight(u^3+v^3=(u+v)(u^2-uv+v^2))}}}
{{{3ab(a+b)(a^2-ab+b^2)}}}
Happy Calculating!!!