Question 585148
1) Find the product of (x^2 - 3x + 2) with the quotient of (6x^6 - 9x^5 - 3x^3) ÷ 3x^3. 
:
You can cancel 3x^3 into each term:
{{{(6x^6 - 9x^5 - 3x^3)/(3x^3)}}} = 2x^3 - 3x^2 - 1 
then the product
{{{(2x^3 - 3x^2 - 1)*(x^2 - 3x + 2)}}} = {{{2x^5 - 9x^4 + 13x^3 - 7x^2 + 3x - 2}}}