Question 585123
Can you please help me solve this problem, thank you.
The equation of the line perpendicular to 3x+2y=8 and containing (6,-2) is:
Formula: y=mx+b
3x+2y=8
-3x -3x
2y=-3x+8
then i divided 2y by 2 and -3x+8 by 2
y=-3/2x+4
Right here you have to determine the slope of the perpendicular line
the relationship of slopes of perpendicular lines: m1*m2 = -1
m1 = {{{-3/2}}}
m2 = slope of perpendicular line
{{{-3/2}}}*m2 = -1
m2 = -1 * {{{-2/3}}}
m2 = {{{2/3}}} the slope of the perpendicular line
:
Use the point/slope form to find the equation: y - y1 = m(x - x1)
m = {{{2/3}}}
x1 = 6
y2 = -2
y - (-2) = {{{2/3}}}(x - 6)
y + 2 = {{{2/3}}}x - 4
y = {{{2/3}}}x - 4 - 2
y = {{{2/3}}}x - 6; the equation of the perpendicular line
:
Graphically
{{{ graph( 300, 300, -12, 10, -10, 10, -1.5x+4, (2/3)x-6) }}}