Question 585033
Say the distance around the track is {{{K}}} ft
The time for the faster rabbit is {{{ K/11 }}} sec
to go completely around.
In this amount of time, the slower rabbit has gone
{{{ 8*(K/11) = (8/11)*K }}} ft
The slower rabbit has to go some whole multiple 
of {{{ K }}} in order to meet the faster rabbit
at the starting point
The 1st whole multiple of {{{K}}} is {{{ 11*(8/11)*K }}}
where {{{11}}} is the number of times around
for the slower rabbit
----------------------
Excluding the start and finish, they meet
{{{ 11 - 2 = 9 }}} times
Hope I got it