Question 585027
After 1st year:
39k + {{{ .09*39000 = 3519 }}} = 42,510
After 2nd year:
42,510 + {{{ .09*42510 = 3825.9 }}} = 46335.90
The formula for this is:
{{{ s = 39000*( 1 + .09 )^y }}}
where {{{y}}} is the year before the one she's in
so, if she's in her 3rd year:
{{{ s = 39000*( 1 + .09 )^2 }}}
{{{ s = 39000*1.09^2 }}}
{{{ s = 39000*1.1881 }}}
{{{ s = 46335.9 }}}
So, if she's in her 5th year
{{{ s = 39000*( 1 + .09 )^4 }}}
{{{ s = 39000*1.4115816 }}}
{{{ s = 55051.68 }}}
Her salary during her 5th year is $55,051.68 
I think this is right, but you can get a 2nd opinion, too