Question 585018
p-q = 3


(x-p)(x-q)


x^2-xp-xq+pq


x^2-(p+q)x+pq



-(p+q)=-6


p+q=6

p-q=3



2p=9

p = 9/2


p+q = 6


9/2+q = 6


q = 6-9/2


q = 3/2



-----------------------


(x-p)(x-q)


x^2-xp-xq+pq


x^2-(p+q)x+pq


x^2-(9/2+3/2)x+(9/2)(3/2)


x^2-6x+27/4



So the value of 'k' is {{{k=27/4}}}