Question 584914
(4^2)^4 * (4^2)^(-5)


4^(2*4)*(4^(2*(-5)))


4^8*4^(-10)


4^(8+(-10))


4^(-2)


1/4^2


1/16



So (4^2)^4 * (4^2)^(-5) = 1/16

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