Question 584793
Let the measures of equal sides be x and the measure of the shortest side be y.

Also, it is given that the measure of equal sides is double of the shortest side.

So,   x = 2y        ----------- (1)

We know that perimeter of triangle is sum of all the three sides.

Therefore,  x + x + y = 36

or  2y + 2y + y = 36   {Using equation (1)  x = 2y}
5y = 36
y = 36/5

Using equation (1),
x = 2y = 2*(36/5) = 72/5

Hence, the sides of triangle are 72/5, 72/5 and 36/5