Question 584714
Let x and y be the two numbers whose sum is 100 such that x>y.

So,  x + y = 100       ------------- (1)

Also, larger number is 10 more than twice the smaller.

Therefore,   x = 2y + 10
   100 - y = 2y + 10    {Using equation (1) }
90 = 3y
Dividing both the sides by 3, we get:

90/3 = y
or  y = 30

Plugging back the value of y in equation (1), we get:
x = 100 - y
x = 100 -30
x = 70

Thus, the larger number is 70 and the smaller number is 30.