Question 584363
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*[tex \LARGE 1\,\frac{7}{8}\ +\ \frac{3}{8}\ =\ 2\,\frac{2}{8}\ =\ 2\,\frac{1}{4}\ =\ 2.25] inches per row.


*[tex \LARGE 7\ \times\ 12\ =\ 84], *[tex \LARGE 84\ +\ 6\ =\ 90] so seven and a half feet is 90 inches.


How many times will *[tex \LARGE 2\,\frac{1}{4}] inches fit into 90 inches?  Divide 90 by 2.25.


This assumes you lay the first course with no mortar beneath it (very dumb idea) or there is no layer of mortar on top of the last row of bricks.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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