Question 584076
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Step 1:  Put your equation into standard form, thus:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ ax^2\ +\ bx\ +\ c\ =\ 0]


For your problem, 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ =\ 7\ \ ], *[tex \LARGE b\ =\ -2\ \ ], and *[tex \LARGE c\ =\ -9]


The quadratic formula is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{-b\ \pm\ \sqrt{b^2\ -\ 4ac}}{2a}]


Just plug in the values for *[tex \LARGE a], *[tex \LARGE b], and *[tex \LARGE c] and do the arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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