Question 55046
Help please I need to know how to factor this problem x^5-4x^3-8x^2+32
ans:
x^5-4x^3-8x^2+32=x^3(x^2-4)-8(x^2-4)=(x^3-8)(x^2-4)
=(x-2)(x^2+2x+4)(x-2)(x+2)    [ since a^3-b^3=(a-b)(a^2+ab+b^2)  and
                                     (a^2-b^2)=(a+b)(a-b)]