<PRE><B>Question 583603</B>
a cyclist rode the first 36-mile portion of his workout at a constant speed.
For the 30-mile cooldown portion of his workout, he reduced his speed by 2 miles per hour.
 Each portion of the workout took the same time.
Find the cyclist&#39;s speed during the first portion and find his speed during the cooldown portion.
:
let s = his speed on the 1st 36 mi
then
(s-2) = his speed on the last 30 mi
:
Write time equation, time = dist/speed
:
workout time = cooldown time
{{{36/s}}} = {{{30/(s-2)}}}
Cross multiply
36(s-2) = 30s
36s - 72 = 30s
36s - 30s = 72
6s = 72
s = 12 mph his workout speed
then
10 mph his cooldown speed
:
:
Check this by finding the actual times, they should be equal
36/12 = 3 hrs
30/10 = 3 hrs</PRE>