Question 54974
multiply 3x^2- 7x+ 2/x^2+ 6x -16 * x+8/4x-8
ans:
(3x^2-7x+2) = 3x^2-6x-x+2=3x(x-2)-1(x-2)=(3x-1)(x-2)
and (x^2+6x-16)=x^2+8x-2x-16=x(x+8)-2(x+8)=(x-2)(x+8)
hence ((3x^2-7x+2)/(x^2+6x-16))*(x+8)/(4x-8)
or  ((3x-1)(x-2))/((x-2)(x+8))*((x+8)/(4x-8))
or  ((3x-1)/(x+8))*((x+8)/(4x-8))
or  (3x-1)/(4x-8)=(3x-1)/4(x-2)