Question 583590
{{{ x=sqrt(30x^6/40x)}}}
reduce fraction
{{{ x=sqrt(3x^5/4)}}}
factor to reveal some perfect squares
{{{ x=sqrt((3x^2*x^2*x)/4)}}}
extract the square root of those square
{{{ x=(1/2)*x*x*sqrt(3x)}}} =  {{{x^2/2}}} * {{{sqrt(3x)}}}
multiply both sides by 2
2x = {{{x^2*sqrt(3x)}}}
divide both sides by x
2 = {{{x*sqrt(3x)}}}
square both sides
4 = x^2(3x)
4 = 3x^3
x^3 = {{{4/3}}}
x = {{{3sqrt(4/3)}}}; (cube root of 4/3)
x ~ 1.10064