Question 55030
(13y-5)(2y+4)(y+2)
=(13y-5)(2y^2+8y+8)
=13y(2y^2++8y+8)-5(2y^2+8y+8)
=26y^3+104y^2+104y-10y^2-40x-40
=26y^3+94y^2+64y-40
Cheers,
stan H.