Question 583561
I am having trouble finding the midpoint of the square roots. I got one of the problems right, but now I can't seem to get this one right. Please help!

(2 square root of 5, 3 square root of 3) (3 square root of 5, negative square root of 3) 
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If those are 2 points and you want the mid-point:
Find the average of x & y separately.
For x: {{{(2sqrt(5) + 3sqrt(5))/2 = 2.5sqrt(5)}}}
For y: {{{(3sqrt(3) - sqrt(5))/2 = sqrt(3)}}}
--> (5sqrt(5)/2,sqrt(3))