Question 583540
thanks for posting i love these problems
{{{a+b=53}}} ( two numbers a and b)
{{{a<b}}} ( a is less than b)
{{{3a=19+b}}} ( three times a is 19 more than b)
{{{3a-19=b}}} ( subtracted 19 to find what b equals)
{{{a+3a-19=53}}} (substituted 3a-19 for b)
{{{4a=72}}} (added like terms and added 19 to both sides)
{{{a=18}}}
{{{53-18=35}}} (subtracted a from total to find b)
{{{b=35}}}