Question 583466
4      	x	+	20	y  	=	15				
Find the slope of this line										
										
20	y  	=	-4      	x	+	15    				
Divide by	20									
	y  	=	-  1/ 5	x	+	 3/4				
Compare this equation with y=mx+b,					m= slope & b= y intercept					
slope m =	- 1/5									
										
The slope of a line perpendicular to the above line will be the negative reciprocal										5    
m1*m2=-1										
The slope of the required line will be			5    							
										
m=	5    	,point	(	-1	,	20	)			
Find b by plugging the values of m & the point in										
y=mx+b										
20	=	-5      	+	b						
b=	25    									
m=	5    									
The required equation isy  =	5 x+25      			
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