<PRE><B>Question 583461</B>
x1		y1	x2	y2				
4		-4	-2	4				
								
slope m =		(y2-y1)/(x2-x1)						
(	4	-	-4	)/(	-2	-	4	)
(	8	/	-6	)  				
m=		-4/3	

The slope of a perpendicular line will be the negative reciprocal of this slope
=3/4

slope = 3/4 and it passes through the midpoint of the above two points

mid point formula 
x= (x1+x2)/2 = (4-2)/2=1
y=0

the point is (1,0)

slope = 3/4, point = (1,0)

substitute in y=mx+b

0=3/4 *1+b
b=-3/4

the equation is y=(3/4)x-3/4					 
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