Question 583444
the length of each leg of an isosceles triangle is 5 centemeters more than twice the length of the base. if the perimeter of this isosceles triangle is 95 centemeters, what is the length of the base?.
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Let base length be "x".
Each leg is "2x+5"
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Equation:
x + 2(2x+5) = 95
x + 4x + 10 = 95
5x = 85
x = 17 cm (base length)
2x+5 = 39 cm (length of each base)
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Cheers,
Stan H
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