<PRE><B>Question 583145</B>
Find the value of the discriminant for 9x^2+1=6x. Then describe the number and type of roots for the equation..... I already found the discriminant to be -72 i just dont know how to do the last part
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Disc = 6^2 - 4*9*1 = 0
Not -72
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Disc = 0 --&gt; 2 real roots, same value
For this eqn, x = 1/3, 1/3
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Or, x = 1/3 multiplicity 2
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*[invoke solve_quadratic_equation 9,-6,1]

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