Question 582814


{{{2x-5y=45}}} Start with the given equation.



{{{-5y=45-2x}}} Subtract {{{2x}}} from both sides.



{{{-5y=-2x+45}}} Rearrange the terms.



{{{y=(-2x+45)/(-5)}}} Divide both sides by {{{-5}}} to isolate y.



{{{y=((-2)/(-5))x+(45)/(-5)}}} Break up the fraction.



{{{y=(2/5)x-9}}} Reduce.



So the equation {{{y=(2/5)x-9}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=2/5}}} and the y-intercept is {{{b=-9}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-9\right)]