Question 582857
Students at Broward Community College spend an average of $60 per week for food with a standard deviation of 10. This distribution is normally distributed. 

If 80 different students are randomly sampled; find the probability that their mean expenditure for food is more than $ 75. 

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z(75) = (75-60)/[10/sqrt(80)] = 11.62
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P(x > 75) = P(z > 11.62) = 1.677x10^(-31)
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Cheers,
Stan H.
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