Question 55010
{{{2y(3+4)-4(y+1)=5red(y)+1}}}
or {{{6y+red(8)y-4y-4=5y+1}}}
or {{{10y-4=5y+1}}}
or {{{10y-4 - 5y + 4=5y+1 -5y + 4}}}
or {{{5y = 5}}}
or {{{y = 1}}}

You have done a mistake in first step and also in the second step. I have marked the corrections in red.