<PRE><B>Question 582697</B>
Given &amp;#1256; is an angle in standard position and its terminal side passes through the point(-3,2).
1)Draw a diagram that shows the angle in the coordinate axis.
2)Find the exact values of Sin&amp;#1256;,cos&amp;#1256;,tan&amp;#1256;,sec&amp;#1256;,csc&amp;#1256;, and cot&amp;#1256;
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(-3,2) is in Q2
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tan(theta) = y/x = -3/2
y = 3 and x = -2 in Q2
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Solve for &quot;r&quot;:
r = sqrt(3^2+2^2) = sqrt(13)
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sin = y/r = 2/sqrt(13)
cos = x/r = -2/sqrt(13)
tan = y/x = -3/2
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csc = r/y = sqrt(13)/3
sec = r/x = -sqrt(13)/2
ctn = x/y = -2/3
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Cheers,
Stan H.</PRE>