Question 582644
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(17,-12\right)]. So this means that {{{x[1]=17}}} and {{{y[1]=-12}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-9,-15\right)].  So this means that {{{x[2]=-9}}} and {{{y[2]=-15}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-15--12)/(-9-17)}}} Plug in {{{y[2]=-15}}}, {{{y[1]=-12}}}, {{{x[2]=-9}}}, and {{{x[1]=17}}}



{{{m=(-3)/(-9-17)}}} Subtract {{{-12}}} from {{{-15}}} to get {{{-3}}}



{{{m=(-3)/(-26)}}} Subtract {{{17}}} from {{{-9}}} to get {{{-26}}}



{{{m=3/26}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(17,-12\right)] and *[Tex \LARGE \left(-9,-15\right)] is {{{m=3/26}}}