Question 582595
Please help me solve this equation for all the solutions in the interval [0, 2 pi)  
sin^2x+sinx=0
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Factor:
sin(x)[sinx+1] = 0
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sin(x) = 0 or sin(x) = -1
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x = 0, or pi, or (3/2)pi
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Cheers,
Stan H.