Question 582465
x(2-x)(x+3)^2 = 0


x = 0, 2-x=0, or (x+3)^2 = 0


x = 0, x = 2, or x = -3


The first two zeros of x = 0 and x = 2 are of multiplicity one.


The last zero x = -3 is of multiplicity two.