Question 55003
how much pure acid should be mixed with 2 gallons of a 40% acid solution in order to get a 70% acid solution.
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40% solution DATA;
amount = 2 gallons ; amount of acid = 0.40(2)=0.8 gallons
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100% solution DATA:
amount = x gallons ; amount of acid = 1.00x=x gallons
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70% solution DATA:
amount= 2+x gallons; amount of acid = 0.7(2+x)=1.4 +0.7x gallongs
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EQUATION:
acid + acid = acid
0.8 + x = 1.4+0.7x
0.3x=0.6
x=2 gallons (amount of pure acid that must be added)
Cheers,
stan H.