Question 580965
Let x be the larger number, and y be the smaller number.

The sum of two numbers is 27. So the equation would be:
{{{x+y=27}}}


The larger number is 3 more than the smaller number. So:

larger number = smaller number + 3

or

{{{x = y + 3}}}

Now, we want to get rid of x and solve for y first. Since {{{x=y+3}}}, we can substitute y+3 for x in the equation {{{x+y=27}}}.

Therefore:
(y + 3) + y = 27

Combine like terms:
2y + 3 = 27

Subtract 3 on both sides:
2y = 24

Divide both sides by 2:
y = 12

So the smaller number is 12. The larger number is 3 more than the smaller number, so:

x = 12 + 3
x = 15

The 2 numbers are 12 and 15. Check:

12 + 15 = 27
which is correct.