Question 582093
Factor:
{{{2w^4-26w^3-96w^2}}} Since each term has a common factor of {{{2w^2}}} you can factor this to start.
{{{2w^2(w^2-13w-48)}}} To factor the trinomial, find two integers whose product is -48 and whose sum is -13.
{{{-48 = 3*(-16)}}} and {{{3+(-16) = -13}}}so we get:
{{{2w^2(w-16)(w+3)}}}