Question 581755
Use the general rule
{{{ log(a) + log(b) = log(a*b) }}}
{{{ log(2,x-2) + log(2,x+1) = log(2,10) }}}
{{{ log(2,(x-2)/(x+1)) = log(2,10) }}}
{{{ (x-2)/(x+1) = 10 }}}
{{{ x - 2 = 10*( x + 1 ) }}}
{{{ x - 2 = 10x + 10 }}}
{{{ 9x = -12 }}}
{{{ x = -4/3 }}}
check:
{{{ log(2,(x-2)/(x+1)) }}}
{{{ log(2,(-4/3 - 2)/(-4/3 + 1)) }}}
{{{ log(2,(-4/3 - 6/3)/(-4/3 + 3/3)) }}}
{{{ log(2,(-10/3)/(-1/3)) }}}
{{{ log(2,10) }}}
OK