Question 581669
Quick Method: The y coordinates are the same. Therefore, the slope is 0. Visually, this is a horizontal line (and all horizontal lines have slopes of 0)


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Longer Method:


Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(5,-2\right)]. So this means that {{{x[1]=5}}} and {{{y[1]=-2}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-4,-2\right)].  So this means that {{{x[2]=-4}}} and {{{y[2]=-2}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-2--2)/(-4-5)}}} Plug in {{{y[2]=-2}}}, {{{y[1]=-2}}}, {{{x[2]=-4}}}, and {{{x[1]=5}}}



{{{m=(0)/(-4-5)}}} Subtract {{{-2}}} from {{{-2}}} to get {{{0}}}



{{{m=(0)/(-9)}}} Subtract {{{5}}} from {{{-4}}} to get {{{-9}}}



{{{m=0}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(5,-2\right)] and *[Tex \LARGE \left(-4,-2\right)] is {{{m=0}}}