<PRE><B>Question 581483</B>
If 20 women and 20 men in his statistics course and one class individual is randomly selected. 
1) What is the probability that the individual is a woman?::20/40 = 1/2
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2) What are the odds of the individual selected is a woman?
odds for = P(for)/P(against) = (1/2)/(1/2) = 1:1
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3) What are the odds of the individual selected against being a woman?
odds against = p(against)/P(for) = (1/2)/(1/2) = 1:1
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cheers,
Stan H.
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